waecmaths question:
The nth term of the sequence –2, 4, –8, 16,…. Is given by
Option A:
${{T}_{n}}={{2}^{n}}$
Option B:
${{T}_{n}}={{(-2)}^{n}}$
Option C:
${{T}_{n}}=(-2n)$
Option D:
${{T}_{n}}={{2}^{n}}$
waecmaths solution:
$\begin{align} & {{T}_{1}}=-2={{(-2)}^{-1}} \\ & {{T}_{2}}=4={{(-2)}^{2}} \\ & {{T}_{3}}=8={{(-2)}^{3}} \\ & {{T}_{n}}={{(-2)}^{n}} \\\end{align}$
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