waecmaths question:
H varies directly as p and inversely as the square of y. If H =1, P =8 and y =2, find H in terms of p and y
Option A:
$H=\frac{p}{4{{y}^{2}}}$
Option B:
$H=\frac{2p}{{{y}^{2}}}$
Option C:
$H=\frac{p}{2{{y}^{2}}}$
Option D:
$H=\frac{p}{{{y}^{2}}}$
waecmaths solution:
$\begin{align} & H\propto \frac{p}{{{y}^{2}}} \\ & H=\frac{kp}{{{y}^{2}}}\left| k\text{ is the constant of proportionality} \right. \\ & 1=\frac{k(8)}{{{2}^{2}}} \\ & k=\frac{1}{2} \\ & H=\frac{p}{2{{y}^{2}}} \\\end{align}$
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